4(x)=-2x^2+5x-3

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Solution for 4(x)=-2x^2+5x-3 equation: 



4(x)=-2x^2+5x-3

We move all terms to the left:

4(x)-(-2x^2+5x-3)=0

We get rid of parentheses

2x^2-5x+4x+3=0

We add all the numbers together, and all the variables

2x^2-1x+3=0

a = 2; b = -1; c = +3;
Δ = b2-4ac
Δ = -12-4·2·3
Δ = -23
Delta is less than zero, so there is no solution for the equation

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